-
Notifications
You must be signed in to change notification settings - Fork 0
/
Copy path42.trapping-rain-water.js
50 lines (47 loc) · 1.18 KB
/
42.trapping-rain-water.js
1
2
3
4
5
6
7
8
9
10
11
12
13
14
15
16
17
18
19
20
21
22
23
24
25
26
27
28
29
30
31
32
33
34
35
36
37
38
39
40
41
42
43
44
45
46
47
48
49
50
/*
* @lc app=leetcode id=42 lang=javascript
*
* [42] Trapping Rain Water
*
* https://leetcode.com/problems/trapping-rain-water/description/
*
* algorithms
* Hard (40.39%)
* Total Accepted: 226.5K
* Total Submissions: 560.7K
* Testcase Example: '[0,1,0,2,1,0,1,3,2,1,2,1]'
*
* Given n non-negative integers representing an elevation map where the width
* of each bar is 1, compute how much water it is able to trap after raining.
*
*
* The above elevation map is represented by array [0,1,0,2,1,0,1,3,2,1,2,1].
* In this case, 6 units of rain water (blue section) are being trapped. Thanks
* Marcos for contributing this image!
*
* Example:
*
*
* Input: [0,1,0,2,1,0,1,3,2,1,2,1]
* Output: 6
*
*/
/**
* @param {number[]} height
* @return {number}
*/
function trap(height) {
let total = 0,
left = 0,
right = height.length - 1,
leftMax = 0,
rightMax = 0;
while (left <= right) {
if (leftMax < height[left] ) leftMax = height[left];
if (rightMax < height[right]) rightMax = height[right];
total += (height[left] < height[right])
? leftMax - height[left++]
: rightMax - height[right--];
}
return total;
};